AP Precalculus: Two-Dimensional Vectors
Master vector operations, magnitude, direction, and component form
📚 Understanding Vectors
A vector is a quantity with both magnitude (length) and direction. In two dimensions, vectors can be represented as arrows on a coordinate plane or written in component form. Vectors are essential in physics, engineering, and computer graphics for representing forces, velocities, and displacements.
1 Vector Notation & Basics
A vector in 2D can be written in component form as \(\vec{v} = \langle a, b \rangle\), where \(a\) is the horizontal component and \(b\) is the vertical component.
\(\vec{v} = \langle a, b \rangle = a\mathbf{i} + b\mathbf{j}\). Both forms are equivalent!
2 Component Form from Two Points
Given two points, find the vector from the initial point to the terminal point by subtracting coordinates.
where \(A(x_1, y_1)\) is the initial point and \(B(x_2, y_2)\) is the terminal point
Find: Vector from \(A(2, 3)\) to \(B(7, -1)\)
Calculate: \(\vec{AB} = \langle 7 - 2, -1 - 3 \rangle = \langle 5, -4 \rangle\)
3 Magnitude of a Vector
The magnitude (or length) of a vector is its distance from the origin, calculated using the Pythagorean theorem.
Find: \(|\langle 3, -4 \rangle|\)
Calculate: \(\sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\)
4 Direction Angle
The direction angle \(\theta\) is the angle the vector makes with the positive x-axis, measured counterclockwise.
The basic arctan formula only gives angles in Quadrants I and IV. Add \(180°\) (or \(\pi\)) for Quadrants II and III!
Find direction of: \(\vec{v} = \langle -3, 3 \rangle\)
Reference angle: \(\arctan\left|\frac{3}{-3}\right| = \arctan(1) = 45°\)
Quadrant: \(a < 0, b> 0\) → Quadrant II
Direction: \(\theta = 180° - 45° = 135°\)
5 Component Form from Magnitude & Direction
Given magnitude \(r\) and direction angle \(\theta\), find the component form of the vector.
Given: Magnitude = 6, Direction = 60°
Components: \(\vec{v} = \langle 6\cos 60°, 6\sin 60° \rangle = \langle 6 \cdot \frac{1}{2}, 6 \cdot \frac{\sqrt{3}}{2} \rangle = \langle 3, 3\sqrt{3} \rangle\)
6 Vector Addition & Subtraction
Add or subtract vectors by combining their corresponding components.
Geometric Methods
- Draw the first vector
- Place the tail of the second vector at the tip of the first
- The resultant goes from the start of the first to the end of the second
- Draw both vectors from the same point
- Complete the parallelogram
- The diagonal from the common point is the resultant
Add: \(\langle 4, -2 \rangle + \langle -1, 5 \rangle\)
Sum: \(\langle 4 + (-1), -2 + 5 \rangle = \langle 3, 3 \rangle\)
7 Magnitude & Direction of Resultant
After adding vectors to get the resultant, find its magnitude and direction using the standard formulas.
Given: \(\vec{R} = \langle 3, 3 \rangle\) (from previous example)
Magnitude: \(|\vec{R}| = \sqrt{3^2 + 3^2} = \sqrt{18} = 3\sqrt{2}\)
Direction: \(\theta = \arctan\left(\frac{3}{3}\right) = \arctan(1) = 45°\)
8 Scalar Multiplication
Scalar multiplication multiplies each component by a constant (scalar), changing the vector's length but not its direction (unless negative).
If \(k > 0\)
Same direction, magnitude multiplied by \(k\)
If \(k < 0\)
Opposite direction, magnitude = \(|k| \cdot |\vec{v}|\)
If \(|k| > 1\)
Vector is stretched (longer)
If \(0 < |k| < 1\)
Vector is compressed (shorter)
Calculate: \(-2 \cdot \langle 3, -4 \rangle = \langle -6, 8 \rangle\)
Effect: Doubled in length, reversed direction
9 Unit Vector
A unit vector has magnitude 1 and points in the same direction as the original vector.
Find unit vector in direction of: \(\vec{v} = \langle 3, 4 \rangle\)
Magnitude: \(|\vec{v}| = 5\)
Unit vector: \(\hat{u} = \frac{1}{5}\langle 3, 4 \rangle = \left\langle \frac{3}{5}, \frac{4}{5} \right\rangle\)
Check that \(|\hat{u}| = 1\): \(\sqrt{\left(\frac{3}{5}\right)^2 + \left(\frac{4}{5}\right)^2} = \sqrt{\frac{9+16}{25}} = 1\) ✓
10 Linear Combinations
A linear combination of vectors combines scalar multiples of multiple vectors.
Calculate: \(2\langle 1, 3 \rangle + 3\langle -2, 1 \rangle\)
= \(\langle 2, 6 \rangle + \langle -6, 3 \rangle\)
= \(\langle 2 + (-6), 6 + 3 \rangle = \langle -4, 9 \rangle\)
📋 Quick Reference
Magnitude
\(|\vec{v}| = \sqrt{a^2 + b^2}\)
Direction
\(\theta = \arctan\left(\frac{b}{a}\right)\)
Components from Polar
\(\langle r\cos\theta, r\sin\theta \rangle\)
Vector Addition
\(\langle a+c, b+d \rangle\)
Scalar Multiply
\(k\langle a, b \rangle = \langle ka, kb \rangle\)
Unit Vector
\(\hat{u} = \frac{\vec{v}}{|\vec{v}|}\)
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