IB Mathematics AI – Topic 3
Geometry & Trigonometry: Trigonometry
Overview: Trigonometry studies relationships between angles and sides in triangles. Essential for solving real-world problems involving heights, distances, and angles.
Key Strategy: Identify triangle type (right or non-right) → Choose appropriate formula → Use GDC for calculations
Right-Angled Triangle Trigonometry
SOH CAH TOA
Definition: In a right-angled triangle, trigonometric ratios relate the angles to the sides.
The Three Basic Ratios:
Sine (sin):
\[ \sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}} \]
Cosine (cos):
\[ \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \]
Tangent (tan):
\[ \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} \]
Memory Aid - SOH CAH TOA:
- Sine = Opposite / Hypotenuse
- Cosine = Adjacent / Hypotenuse
- Tangent = Opposite / Adjacent
Pythagorean Theorem:
\[ a^2 + b^2 = c^2 \]
where c is the hypotenuse
⚠️ Common Pitfalls & Tips:
- Identify which side is opposite/adjacent to the given angle
- Hypotenuse is ALWAYS the longest side (opposite the right angle)
- Check calculator is in correct mode (degrees or radians)
- Use inverse functions (sin⁻¹, cos⁻¹, tan⁻¹) to find angles
Sine Rule (Non-Right Triangles)
For Any Triangle
Definition: The sine rule relates the sides of a triangle to the sines of the opposite angles. Works for ANY triangle.
Sine Rule Formula:
\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \]
Or equivalently:
\[ \frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c} \]
where a, b, c are sides opposite to angles A, B, C respectively
When to Use Sine Rule:
- When you know: AAS (two angles and one side)
- When you know: ASA (angle-side-angle)
- When you know: SSA (two sides and non-included angle) - ambiguous case
Finding a Side:
Use the form: \(\frac{a}{\sin A} = \frac{b}{\sin B}\)
Finding an Angle:
Use the form: \(\frac{\sin A}{a} = \frac{\sin B}{b}\)
⚠️ Common Pitfalls & Tips:
- Ambiguous case (SSA): May have 0, 1, or 2 solutions
- Label triangle clearly: side a opposite angle A, etc.
- Use GDC to avoid calculation errors
- Check answer is reasonable (angles sum to 180°)
📝 Worked Example 1: Using Sine Rule
Question: In triangle ABC, angle A = 40°, angle B = 65°, and side b = 12 cm. Find side a.
Solution:
Given: A = 40°, B = 65°, b = 12 cm
Need to find: a
Step 1: Apply Sine Rule
\[ \frac{a}{\sin A} = \frac{b}{\sin B} \]
Step 2: Substitute values
\[ \frac{a}{\sin 40°} = \frac{12}{\sin 65°} \]
Step 3: Solve for a
\[ a = \frac{12 \times \sin 40°}{\sin 65°} \]
\[ a \approx \frac{12 \times 0.6428}{0.9063} \approx 8.51 \text{ cm} \]
Answer: a = 8.51 cm (3 s.f.)
Cosine Rule (Non-Right Triangles)
For Any Triangle
Cosine Rule Formula (for finding a side):
\[ c^2 = a^2 + b^2 - 2ab\cos C \]
Or equivalently for other sides:
\[ a^2 = b^2 + c^2 - 2bc\cos A \]
\[ b^2 = a^2 + c^2 - 2ac\cos B \]
Cosine Rule (for finding an angle):
\[ \cos C = \frac{a^2 + b^2 - c^2}{2ab} \]
When to Use Cosine Rule:
- When you know: SAS (two sides and included angle)
- When you know: SSS (all three sides)
- When sine rule cannot be used
⚠️ Common Pitfalls & Tips:
- The angle in the formula is BETWEEN the two known sides
- Don't forget the -2ab cos C term (not +)
- When finding angle, use cos⁻¹ function on GDC
- Check calculator mode (degrees or radians)
Area of Triangles
Multiple Formulas
1. Basic Formula (with base and height):
\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]
2. Using Sine (two sides and included angle):
\[ \text{Area} = \frac{1}{2}ab\sin C \]
where a and b are two sides, C is the included angle
Most commonly used in IB exams!
3. Heron's Formula (all three sides known):
\[ \text{Area} = \sqrt{s(s-a)(s-b)(s-c)} \]
where \(s = \frac{a+b+c}{2}\) is the semi-perimeter
⚠️ Common Pitfalls & Tips:
- For \(\frac{1}{2}ab\sin C\), angle C must be BETWEEN sides a and b
- Don't forget the 1/2 factor
- Area is always in square units (cm², m²)
- Use GDC to calculate - faster and more accurate
📝 Worked Example 2: Finding Area
Question: Triangle PQR has sides PQ = 8 cm, PR = 10 cm, and angle P = 50°. Find the area of the triangle.
Solution:
Given: Two sides and included angle (SAS)
PQ = 8 cm, PR = 10 cm, angle P = 50°
Step 1: Choose appropriate formula
Use: \(\text{Area} = \frac{1}{2}ab\sin C\)
Step 2: Substitute values
\[ \text{Area} = \frac{1}{2} \times 8 \times 10 \times \sin 50° \]
Step 3: Calculate
\[ \text{Area} = \frac{1}{2} \times 80 \times 0.7660 \]
\[ \text{Area} \approx 40 \times 0.7660 = 30.6 \text{ cm}^2 \]
Answer: 30.6 cm²
Radians
Alternative Angle Measurement
Definition: A radian is the angle subtended at the center of a circle by an arc equal in length to the radius.
Conversion Between Degrees and Radians:
\[ 180° = \pi \text{ radians} \]
\[ 360° = 2\pi \text{ radians} \]
Conversion Formulas:
Degrees to Radians:
\[ \text{radians} = \text{degrees} \times \frac{\pi}{180} \]
Radians to Degrees:
\[ \text{degrees} = \text{radians} \times \frac{180}{\pi} \]
Common Radian Values:
- 30° = \(\frac{\pi}{6}\) rad
- 45° = \(\frac{\pi}{4}\) rad
- 60° = \(\frac{\pi}{3}\) rad
- 90° = \(\frac{\pi}{2}\) rad
- 180° = \(\pi\) rad
⚠️ Common Pitfalls & Tips:
- CRITICAL: Check calculator mode matches question units
- Radians don't have a degree symbol (°)
- Use π button on calculator, not 3.14
- Arc length and sector area formulas REQUIRE radians
Arcs and Sectors
Parts of a Circle
Definitions:
- Arc: Part of the circumference of a circle
- Sector: Region bounded by two radii and an arc (like a pizza slice)
- Segment: Region bounded by a chord and an arc
Arc Length (θ in radians):
\[ l = r\theta \]
where r = radius, θ = angle in radians
Arc Length (θ in degrees):
\[ l = \frac{\theta}{360} \times 2\pi r \]
Sector Area (θ in radians):
\[ A = \frac{1}{2}r^2\theta \]
Sector Area (θ in degrees):
\[ A = \frac{\theta}{360} \times \pi r^2 \]
Segment Area:
\[ A_{\text{segment}} = A_{\text{sector}} - A_{\text{triangle}} \]
⚠️ Common Pitfalls & Tips:
- Must use radians for formulas \(l = r\theta\) and \(A = \frac{1}{2}r^2\theta\)
- Convert degrees to radians first if needed
- Arc length has same units as radius (cm, m)
- Sector area has squared units (cm², m²)
Complete Trigonometry Formula Summary
| Type | Formula | When to Use |
|---|---|---|
| Sine Rule | \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\) | AAS, ASA, SSA |
| Cosine Rule | \(c^2 = a^2 + b^2 - 2ab\cos C\) | SAS, SSS |
| Area (sine) | \(A = \frac{1}{2}ab\sin C\) | Two sides + included angle |
| Arc Length | \(l = r\theta\) (radians) | Circle problems |
| Sector Area | \(A = \frac{1}{2}r^2\theta\) (radians) | Circle problems |
📊 Quick Decision Guide
Triangle Type
- Right angle? Use SOH CAH TOA
- No right angle? Use sine or cosine rule
Which Rule?
- AAS/ASA: Sine rule
- SAS/SSS: Cosine rule
Circles
- Convert to radians first!
- Arc: \(l = r\theta\)
- Sector: \(A = \frac{1}{2}r^2\theta\)
Calculator Mode
- Always check mode!
- Degrees (°) or Radians (rad)
- Match question units
✍️ IB Exam Strategy
- Draw a diagram if not provided - label all given information
- Identify triangle type: Right-angled or not?
- Check what you know: SAS, ASA, AAS, SSS, SSA?
- Select appropriate formula from formula booklet
- Verify calculator mode: Degrees or radians?
- Use GDC for all calculations - show setup first
- Check reasonableness: Angles sum to 180°, positive values
- State units: cm, m, degrees, radians, cm², etc.
🚫 Top Mistakes to Avoid
- Calculator in wrong mode (degrees vs radians) - check every time!
- Using sine rule when cosine rule is needed (or vice versa)
- For area formula: angle must be BETWEEN the two sides
- Forgetting to convert degrees to radians for arc/sector formulas
- Not labeling triangle properly (side a opposite angle A)
- Using diameter instead of radius in circle formulas
- Forgetting the 1/2 factor in area formulas
- In cosine rule: using + instead of - before 2ab cos C
- Not checking if answer is reasonable
- Rounding too early - keep full accuracy until final answer