AP Precalculus: Three-Dimensional Vectors
Extend your vector knowledge into 3D space with magnitude, components, and operations
π Vectors in Three Dimensions
Three-dimensional vectors extend 2D concepts by adding a z-component. While 2D vectors lie in a plane, 3D vectors exist in space and are essential for physics, engineering, and computer graphics applications like modeling motion, forces, and 3D rendering.
1 3D Vector Notation & Basics
A three-dimensional vector has three components: \(\vec{v} = \langle a, b, c \rangle\), representing movement along the x, y, and z axes.
Standard Unit Vectors in 3D
\(\vec{v} = \langle a, b, c \rangle = a\mathbf{i} + b\mathbf{j} + c\mathbf{k}\). The \(\mathbf{k}\) vector is the new unit vector along the z-axis.
2 Component Form from Two Points
Find the vector from point P to point Q by subtracting corresponding coordinates.
where \(P(x_1, y_1, z_1)\) and \(Q(x_2, y_2, z_2)\)
Find: Vector from \(P(1, -2, 3)\) to \(Q(4, 5, -1)\)
Calculate: \(\vec{PQ} = \langle 4-1, 5-(-2), -1-3 \rangle = \langle 3, 7, -4 \rangle\)
3 Magnitude of a 3D Vector
The magnitude of a 3D vector is calculated using an extended version of the Pythagorean theorem.
2D Magnitude
\(\sqrt{a^2 + b^2}\)
3D Magnitude
\(\sqrt{a^2 + b^2 + c^2}\)
Find: \(|\langle 2, -3, 6 \rangle|\)
Calculate: \(\sqrt{2^2 + (-3)^2 + 6^2} = \sqrt{4 + 9 + 36} = \sqrt{49} = 7\)
4 Distance Between Two Points in 3D
The distance between two points in 3D is the magnitude of the vector connecting them.
Find distance from: \(A(1, 2, 3)\) to \(B(4, 6, 3)\)
Calculate: \(d = \sqrt{(4-1)^2 + (6-2)^2 + (3-3)^2} = \sqrt{9 + 16 + 0} = \sqrt{25} = 5\)
5 Vector Addition & Subtraction
Add or subtract 3D vectors by combining their corresponding components, just like in 2D.
Add: \(\langle 2, -1, 4 \rangle + \langle 3, 5, -2 \rangle\)
Sum: \(\langle 2+3, -1+5, 4+(-2) \rangle = \langle 5, 4, 2 \rangle\)
6 Scalar Multiplication
Scalar multiplication multiplies each component by the scalar constant.
Magnitude Effect
\(|k\vec{v}| = |k| \cdot |\vec{v}|\)
Direction Effect
Same if \(k > 0\), opposite if \(k < 0\)
Calculate: \(-3\langle 1, -2, 4 \rangle = \langle -3, 6, -12 \rangle\)
7 Unit Vector in 3D
A unit vector has magnitude 1 and points in the same direction as the original vector.
Find unit vector in direction of: \(\vec{v} = \langle 2, -3, 6 \rangle\)
Magnitude: \(|\vec{v}| = \sqrt{4 + 9 + 36} = 7\)
Unit vector: \(\hat{u} = \frac{1}{7}\langle 2, -3, 6 \rangle = \left\langle \frac{2}{7}, -\frac{3}{7}, \frac{6}{7} \right\rangle\)
Check: \(\left(\frac{2}{7}\right)^2 + \left(-\frac{3}{7}\right)^2 + \left(\frac{6}{7}\right)^2 = \frac{4+9+36}{49} = \frac{49}{49} = 1\) β
8 Linear Combinations
A linear combination combines scalar multiples of multiple vectors.
Calculate: \(2\langle 1, 0, 3 \rangle + 3\langle -1, 2, 1 \rangle\)
= \(\langle 2, 0, 6 \rangle + \langle -3, 6, 3 \rangle\)
= \(\langle 2-3, 0+6, 6+3 \rangle = \langle -1, 6, 9 \rangle\)
9 Comparing 2D and 3D Vectors
Most 2D vector operations extend naturally to 3D by adding a third component.
| Operation | 2D | 3D |
|---|---|---|
| Component Form | \(\langle a, b \rangle\) | \(\langle a, b, c \rangle\) |
| Magnitude | \(\sqrt{a^2 + b^2}\) | \(\sqrt{a^2 + b^2 + c^2}\) |
| Unit Vectors | \(\mathbf{i}, \mathbf{j}\) | \(\mathbf{i}, \mathbf{j}, \mathbf{k}\) |
| Addition | \(\langle a+c, b+d \rangle\) | \(\langle a+d, b+e, c+f \rangle\) |
| Scalar Multiply | \(\langle ka, kb \rangle\) | \(\langle ka, kb, kc \rangle\) |
π Quick Reference
3D Magnitude
\(\sqrt{a^2 + b^2 + c^2}\)
3D Distance
\(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}\)
Unit Vectors
\(\mathbf{i}, \mathbf{j}, \mathbf{k}\)
Unit Vector
\(\hat{u} = \frac{\vec{v}}{|\vec{v}|}\)
Scalar Multiply
\(k\langle a,b,c \rangle = \langle ka, kb, kc \rangle\)
Vector Addition
\(\langle a+d, b+e, c+f \rangle\)
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