AP Precalculus: Nonlinear Inequalities

Master quadratic and polynomial inequalities using sign charts and interval notation

πŸ“ˆ Quadratic πŸ“Š Polynomial ±️ Sign Charts πŸ“ Intervals

πŸ“š Understanding Nonlinear Inequalities

Nonlinear inequalities involve quadratic, polynomial, or rational expressions. Unlike linear inequalities (which create half-planes), these create more complex solution regions. The key technique is finding critical points and testing signs in each interval.

1 Understanding Quadratic Inequalities

A quadratic inequality compares a quadratic expression to zero. The solution is a set of intervals on the number line where the inequality is true.

Standard Forms \(ax^2 + bx + c > 0\), \(ax^2 + bx + c \geq 0\), \(ax^2 + bx + c < 0\), \(ax^2 + bx + c \leq 0\)

What Solutions Mean Graphically

\(f(x) > 0\)
Where parabola is ABOVE x-axis
\(f(x) < 0\)
Where parabola is BELOW x-axis
\(f(x) \geq 0\)
Above OR on x-axis
\(f(x) \leq 0\)
Below OR on x-axis
πŸ’‘ Key Insight

The roots (zeros) of the quadratic are the x-intercepts where the parabola crosses from positive to negative (or vice versa). These are the boundaries of your solution intervals!

2 Solving Quadratic Inequalities Step-by-Step

Use the sign chart method to systematically determine where the quadratic expression is positive or negative.

The 5-Step Process

  1. Rewrite in standard form: Get \(ax^2 + bx + c\) compared to 0
  2. Find the roots: Solve \(ax^2 + bx + c = 0\) using factoring, quadratic formula, etc.
  3. Mark critical points: Place roots on a number line, dividing it into intervals
  4. Test each interval: Pick a test point in each interval and evaluate the sign
  5. Write the solution: Use interval notation, including endpoints if \(\leq\) or \(\geq\)
πŸ“Œ Complete Example

Solve: \(x^2 - 5x + 6 < 0\)

Step 1: Already in standard form

Step 2: Factor: \((x-2)(x-3) = 0\) β†’ roots: \(x = 2\) and \(x = 3\)

Step 3: Critical points divide number line into: \((-\infty, 2)\), \((2, 3)\), \((3, \infty)\)

Step 4: Test points:

Interval
\((-\infty, 2)\)
\((2, 3)\)
\((3, \infty)\)
Test Point
\(x = 0\)
\(x = 2.5\)
\(x = 4\)
\(f(x)\) Value
\(6\)
\(-0.25\)
\(2\)
Sign
+
βˆ’
+

Step 5: We want \(< 0\) (negative), so Solution: \((2, 3)\)

Note: Parentheses because \(<\) means endpoints NOT included

3 Impact of Parabola Direction

The sign of the leading coefficient \(a\) determines whether the parabola opens up or down, which affects where the function is positive or negative.

\(a > 0\) β€” Opens Upward βˆͺ

β€’ Positive on the outside intervals
β€’ Negative between the roots
β€’ \(f(x) > 0\): \((-\infty, r_1) \cup (r_2, \infty)\)
β€’ \(f(x) < 0\): \((r_1, r_2)\)

\(a < 0\) β€” Opens Downward ∩

β€’ Negative on the outside intervals
β€’ Positive between the roots
β€’ \(f(x) > 0\): \((r_1, r_2)\)
β€’ \(f(x) < 0\): \((-\infty, r_1) \cup (r_2, \infty)\)

πŸ“Œ Example: Downward Parabola

Solve: \(-x^2 + 4x - 3 \geq 0\)

Factor: \(-(x-1)(x-3) = 0\) β†’ roots: \(x = 1\), \(x = 3\)

Since \(a < 0\): Parabola opens down β†’ positive BETWEEN roots

Solution: \([1, 3]\) (brackets for \(\geq\))

4 Special Cases: No Real Roots or One Root

When the discriminant \(b^2 - 4ac\) is zero or negative, the quadratic has special solution sets.

No Real Roots (\(b^2 - 4ac < 0\))

Parabola doesn't cross x-axis

If \(a > 0\): Always positive
β€’ \(f(x) > 0\): All real numbers
β€’ \(f(x) < 0\): No solution

One Real Root (\(b^2 - 4ac = 0\))

Parabola touches x-axis at vertex

If \(a > 0\): Only equals 0 at vertex
β€’ \(f(x) > 0\): All except vertex
β€’ \(f(x) \geq 0\): All real numbers

πŸ“Œ Example: No Real Roots

Solve: \(x^2 + 2x + 5 > 0\)

Discriminant: \(4 - 20 = -16 < 0\) β†’ no real roots

Since \(a = 1 > 0\): Parabola opens up and stays above x-axis

Solution: \((-\infty, \infty)\) or "all real numbers"

5 Higher-Degree Polynomial Inequalities

For polynomials of degree 3 or higher, the same sign chart method applies. Find all real roots and test intervals.

Steps for Higher-Degree

  1. Write inequality with polynomial compared to 0
  2. Factor completely to find all real roots
  3. Place all roots on number line (creating \(n+1\) intervals for \(n\) distinct roots)
  4. Test one point in each interval
  5. Write solution using interval notation
πŸ“Œ Example: Cubic Inequality

Solve: \(x^3 - 4x \leq 0\)

Factor: \(x(x^2 - 4) = x(x-2)(x+2) = 0\)

Roots: \(x = -2, 0, 2\)

Intervals: \((-\infty, -2)\), \((-2, 0)\), \((0, 2)\), \((2, \infty)\)

Test:

β€’ \(x = -3\): \((-3)(-5)(-1) = -15 < 0\) βœ“

β€’ \(x = -1\): \((-1)(-3)(1) = 3 > 0\)

β€’ \(x = 1\): \((1)(-1)(3) = -3 < 0\) βœ“

β€’ \(x = 3\): \((3)(1)(5) = 15 > 0\)

Solution: \((-\infty, -2] \cup [0, 2]\)

6 Multiplicity and Sign Changes

The multiplicity of a root determines whether the polynomial changes sign at that point.

Odd Multiplicity (1, 3, 5, ...)
Graph CROSSES x-axis
Sign CHANGES at this root

Example: \((x-2)^1\) or \((x-2)^3\)
Even Multiplicity (2, 4, 6, ...)
Graph TOUCHES x-axis
Sign does NOT change

Example: \((x-2)^2\) or \((x-2)^4\)
πŸ“Œ Example with Multiplicity

Solve: \((x+1)^2(x-3) > 0\)

Roots: \(x = -1\) (mult. 2), \(x = 3\) (mult. 1)

Sign analysis:

β€’ At \(x = -1\): even multiplicity β†’ sign does NOT change

β€’ At \(x = 3\): odd multiplicity β†’ sign CHANGES

Test \(x = 0\): \((1)^2(-3) = -3 < 0\)

Test \(x = 4\): \((5)^2(1) = 25 > 0\)

Solution: \((3, \infty)\)

πŸ’‘ Shortcut Using Multiplicity

Once you know the sign of one interval, you can determine others by tracking sign changes at each root. Only odd multiplicity roots flip the sign!

7 Rational Inequalities

A rational inequality involves a fraction with polynomials. The critical points include both zeros of the numerator AND zeros of the denominator.

Steps for Rational Inequalities

  1. Move everything to one side: \(\frac{f(x)}{g(x)} \gtrless 0\)
  2. Find zeros of numerator (where expression = 0)
  3. Find zeros of denominator (where expression is undefined)
  4. Place ALL critical points on number line
  5. Test each interval and write solution (exclude denominator zeros!)
πŸ“Œ Example

Solve: \(\frac{x-2}{x+1} \geq 0\)

Numerator = 0: \(x = 2\)

Denominator = 0: \(x = -1\) (undefined here!)

Sign chart:

Interval
\((-\infty, -1)\)
\((-1, 2)\)
\((2, \infty)\)
Sign
+
βˆ’
+

Solution: \((-\infty, -1) \cup [2, \infty)\)

Note: \(x = -1\) excluded (undefined), \(x = 2\) included (β‰₯ means = works)

⚠️ Never Include Undefined Points

Points where the denominator equals zero must ALWAYS be excluded from the solution, even if using \(\leq\) or \(\geq\).

8 Writing Solutions in Interval Notation

Express your final answer using proper interval notation with parentheses and brackets.

  • Parentheses \(( )\) β€” endpoint NOT included (use with \(<\) or \(>\))
  • Brackets \([ ]\) β€” endpoint IS included (use with \(\leq\) or \(\geq\))
  • Union \(\cup\) β€” combines separate intervals
  • Infinity β€” always use parentheses with \(\pm\infty\)
πŸ“Œ Notation Examples

\(x < 3\) β†’ \((-\infty, 3)\)

\(x \geq -2\) β†’ \([-2, \infty)\)

\(-1 < x \leq 4\) β†’ \((-1, 4]\)

\(x < -2\) or \(x> 3\) β†’ \((-\infty, -2) \cup (3, \infty)\)

\(x \leq 1\) or \(x \geq 5\) β†’ \((-\infty, 1] \cup [5, \infty)\)

πŸ“‹ Quick Reference

\(f(x) > 0\)

Where graph is above x-axis

\(f(x) < 0\)

Where graph is below x-axis

Critical Points

Roots of numerator AND denominator

Odd Multiplicity

Crosses axis β†’ sign changes

Even Multiplicity

Touches axis β†’ sign stays same

Sign Chart

Test one point per interval

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