AP Precalculus: Inverse Functions
Master inverse functions with algebraic methods, graphical techniques, and table interpretations
π Understanding Inverse Functions
Inverse functions are a fundamental concept in AP Precalculus that "undo" the work of original functions. This guide covers how to identify, find, and work with inverse functions using algebraic, tabular, and graphical methods. Mastering these skills is essential for success on the AP exam and in advanced mathematics.
1 What is an Inverse Function?
An inverse function \(f^{-1}(x)\) reverses the action of \(f(x)\). If \(f\) takes input \(a\) and produces output \(b\), then \(f^{-1}\) takes input \(b\) and returns \(a\).
The composition of a function with its inverse equals the identity function
Essential Properties of Inverse Functions
- Only one-to-one functions (functions that pass the horizontal line test) have inverse functions
- The domain of \(f\) becomes the range of \(f^{-1}\) and vice versa
- The graph of \(f^{-1}\) is a reflection of \(f\) over the line \(y = x\)
- If \(f(a) = b\), then \(f^{-1}(b) = a\) β input and output are swapped
\(f^{-1}(x)\) is NOT the same as \(\frac{1}{f(x)}\). The superscript "-1" denotes the inverse function, not a reciprocal. For example, \(\sin^{-1}(x) \neq \frac{1}{\sin(x)}\).
If \(f\) is a function that doubles a number and adds 3:
\(f(x) = 2x + 3\)
Then \(f^{-1}\) must undo this: subtract 3, then divide by 2:
\(f^{-1}(x) = \frac{x - 3}{2}\)
Verification: \(f(f^{-1}(5)) = f(1) = 2(1) + 3 = 5\) β
2 Finding Inverse Functions Algebraically
To find the inverse function algebraically, you essentially swap the roles of \(x\) and \(y\) and solve for the new \(y\). This reverses the input-output relationship.
Step-by-Step Method
- Replace \(f(x)\) with \(y\) β Write the function as \(y = f(x)\)
- Swap \(x\) and \(y\) β Interchange the variables to get \(x = f(y)\)
- Solve for \(y\) β Isolate \(y\) on one side of the equation
- Write the inverse β Replace \(y\) with \(f^{-1}(x)\)
- Verify (optional) β Check that \(f(f^{-1}(x)) = x\)
Find the inverse of: \(f(x) = 2x + 3\)
Step 1: \(y = 2x + 3\)
Step 2: \(x = 2y + 3\) (swap \(x\) and \(y\))
Step 3: \(x - 3 = 2y\) β \(y = \frac{x - 3}{2}\)
Step 4: \(f^{-1}(x) = \frac{x - 3}{2}\)
Find the inverse of: \(f(x) = \frac{3x + 1}{x - 2}\)
Step 1: \(y = \frac{3x + 1}{x - 2}\)
Step 2: \(x = \frac{3y + 1}{y - 2}\)
Step 3: \(x(y - 2) = 3y + 1\) β \(xy - 2x = 3y + 1\) β \(xy - 3y = 2x + 1\) β \(y(x - 3) = 2x + 1\) β \(y = \frac{2x + 1}{x - 3}\)
Step 4: \(f^{-1}(x) = \frac{2x + 1}{x - 3}\)
Find the inverse of: \(f(x) = x^3 - 5\)
Step 1: \(y = x^3 - 5\)
Step 2: \(x = y^3 - 5\)
Step 3: \(x + 5 = y^3\) β \(y = \sqrt[3]{x + 5}\)
Step 4: \(f^{-1}(x) = \sqrt[3]{x + 5}\)
Always check your answer by verifying \(f(f^{-1}(x)) = x\). Substitute your inverse into the original function and simplify β you should get \(x\).
3 Finding Inverse Values from Tables
When given a table of values for a function \(f\), you can find values of the inverse function \(f^{-1}\) by reversing the input-output pairs. The key insight is: if \(f(a) = b\), then \(f^{-1}(b) = a\).
How to Read Inverse Values from a Table
- To find \(f^{-1}(b)\), locate \(b\) in the output column (usually labeled \(f(x)\) or \(y\))
- The corresponding value in the input column (usually labeled \(x\)) is \(f^{-1}(b)\)
- Essentially, you're searching the \(f(x)\) column and returning the matching \(x\) value
Given table for \(f(x)\):
| \(x\) | \(f(x)\) |
|---|---|
| 1 | 5 |
| 2 | 6 |
| 3 | 8 |
| 4 | 9 |
| 5 | 12 |
Find these inverse values:
\(f^{-1}(5) = 1\) β because \(f(1) = 5\)
\(f^{-1}(6) = 2\) β because \(f(2) = 6\)
\(f^{-1}(9) = 4\) β because \(f(4) = 9\)
\(f^{-1}(12) = 5\) β because \(f(5) = 12\)
The \(f(x)\) column becomes the new \(x\) column, and the original \(x\) column becomes the new \(f^{-1}(x)\) column.
4 Finding Inverse Functions from Graphs
The graph of an inverse function \(f^{-1}\) is the reflection of the graph of \(f\) over the line \(y = x\). This means every point \((a, b)\) on \(f\) becomes \((b, a)\) on \(f^{-1}\).
Key Graphical Concepts
- The line \(y = x\) acts as a "mirror" between \(f\) and \(f^{-1}\)
- Intercepts swap: The \(x\)-intercept of \(f\) becomes the \(y\)-intercept of \(f^{-1}\)
- Points where \(f\) crosses \(y = x\) are fixed points β they appear on both graphs
- If \(f\) is increasing, \(f^{-1}\) is also increasing; same for decreasing
If the graph of \(f\) passes through the points:
β’ \((2, 7)\) β then \(f^{-1}(7) = 2\)
β’ \((-1, 4)\) β then \(f^{-1}(4) = -1\)
β’ \((0, 3)\) β then \(f^{-1}(3) = 0\) (this is the \(y\)-intercept becoming an \(x\)-intercept)
No horizontal line intersects the graph more than once.
To sketch \(f^{-1}\): (1) Plot the line \(y = x\), (2) Take key points from \(f\) and swap their coordinates, (3) Connect the new points maintaining the same curve shape reflected over \(y = x\).
5 Inverse Functions vs. Relations
While every relation has an inverse relation (created by swapping all input-output pairs), the inverse is only a function if the original was one-to-one. Non-one-to-one functions require domain restrictions.
When Inverses Aren't Functions
- If \(f\) fails the horizontal line test, its inverse will fail the vertical line test
- Example: \(f(x) = x^2\) (all real \(x\)) β the inverse \(y = \pm\sqrt{x}\) is not a function
- Solution: Restrict the domain to make \(f\) one-to-one, then find the inverse
Function: \(f(x) = x^2\) for all real numbers
Problem: Not one-to-one (e.g., \(f(2) = f(-2) = 4\))
Solution 1: Restrict to \(x \geq 0\)
Inverse: \(f^{-1}(x) = \sqrt{x}\) with domain \(x \geq 0\)
Solution 2: Restrict to \(x \leq 0\)
Inverse: \(f^{-1}(x) = -\sqrt{x}\) with domain \(x \geq 0\)
Be prepared to determine if an inverse exists, and if not, suggest an appropriate domain restriction that makes the function one-to-one.
π Inverse Function Properties Summary
π€ Notation
\(f^{-1}\) means inverse of \(f\), NOT the reciprocal \(\frac{1}{f}\)
π Composition Identity
\(f(f^{-1}(x)) = x\) and \(f^{-1}(f(x)) = x\)
π Graph Relationship
\(f^{-1}\) is the reflection of \(f\) over the line \(y = x\)
βοΈ Domain-Range Swap
Domain of \(f\) = Range of \(f^{-1}\)
Range of \(f\) = Domain of \(f^{-1}\)
π Point Swap
If \((a, b)\) is on \(f\), then \((b, a)\) is on \(f^{-1}\)
β Existence Test
\(f^{-1}\) exists as a function βΊ \(f\) is one-to-one (passes horizontal line test)
Need Help Mastering AP Precalculus?
Our expert tutors provide personalized instruction to help you excel in inverse functions and all AP Precalculus topics.
Book Free Consultation