Sequences & Series
IB Math Analysis & Approaches SL
Complete Formula Guide with Examples & Tips
๐ What Are Sequences and Series?
Sequence: An ordered list of numbers following a specific pattern (e.g., 2, 4, 6, 8, ...)
Series: The sum of the terms in a sequence (e.g., 2 + 4 + 6 + 8 + ...)
These concepts are essential for financial mathematics, modeling real-world phenomena, and advanced calculus topics in IB Math AA SL.
๐ Arithmetic Sequences
Definition
An arithmetic sequence is a sequence where each term differs from the previous term by a constant amount called the common difference (d).
Example:
3, 7, 11, 15, 19, ... (common difference d = 4)
20, 15, 10, 5, 0, ... (common difference d = -5)
๐ nth Term Formula
\[ u_n = u_1 + (n-1)d \]
Where:
- โข \( u_n \) = nth term (the term you want to find)
- โข \( u_1 \) = first term
- โข \( n \) = term number (position in the sequence)
- โข \( d \) = common difference
๐ก How to Find the Common Difference:
\[ d = u_2 - u_1 = u_3 - u_2 = u_{n+1} - u_n \]
๐ Worked Example: Arithmetic Sequence
Find the 20th term of the sequence: 5, 9, 13, 17, ...
Step 1: Identify the given values
\( u_1 = 5 \)
\( d = 9 - 5 = 4 \)
\( n = 20 \)
Step 2: Apply the formula
\( u_{20} = 5 + (20-1) \times 4 \)
\( u_{20} = 5 + 19 \times 4 \)
\( u_{20} = 5 + 76 \)
\( u_{20} = 81 \)
โ The 20th term is 81
โ Arithmetic Series
Definition
An arithmetic series is the sum of the terms in an arithmetic sequence.
๐ Sum of First n Terms
โ ๏ธ Two formulas are provided in the IB Formula Booklet - choose the most convenient one!
Formula 1 (when you know first and last terms):
\[ S_n = \frac{n}{2}(u_1 + u_n) \]
Formula 2 (when you know first term and common difference):
\[ S_n = \frac{n}{2}[2u_1 + (n-1)d] \]
Where:
- โข \( S_n \) = sum of the first n terms
- โข \( n \) = number of terms
- โข \( u_1 \) = first term
- โข \( u_n \) = nth term (last term)
- โข \( d \) = common difference
๐ Worked Example: Arithmetic Series
Find the sum of the first 15 terms of the sequence: 3, 7, 11, 15, ...
Step 1: Identify the given values
\( u_1 = 3 \), \( d = 4 \), \( n = 15 \)
Step 2: Choose the appropriate formula (Formula 2)
\( S_{15} = \frac{15}{2}[2(3) + (15-1)(4)] \)
\( S_{15} = \frac{15}{2}[6 + 14 \times 4] \)
\( S_{15} = \frac{15}{2}[6 + 56] \)
\( S_{15} = \frac{15}{2} \times 62 \)
\( S_{15} = 15 \times 31 = 465 \)
โ The sum of the first 15 terms is 465
๐ Geometric Sequences
Definition
A geometric sequence is a sequence where each term is obtained by multiplying the previous term by a constant value called the common ratio (r).
Example:
2, 6, 18, 54, 162, ... (common ratio r = 3)
80, 40, 20, 10, 5, ... (common ratio r = 0.5)
3, -6, 12, -24, 48, ... (common ratio r = -2)
๐ nth Term Formula
\[ u_n = u_1 \cdot r^{n-1} \]
Where:
- โข \( u_n \) = nth term
- โข \( u_1 \) = first term
- โข \( r \) = common ratio
- โข \( n \) = term number
๐ก How to Find the Common Ratio:
\[ r = \frac{u_2}{u_1} = \frac{u_3}{u_2} = \frac{u_{n+1}}{u_n} \]
๐ Worked Example: Geometric Sequence
Find the 8th term of the sequence: 2, 6, 18, 54, ...
Step 1: Identify the given values
\( u_1 = 2 \)
\( r = \frac{6}{2} = 3 \)
\( n = 8 \)
Step 2: Apply the formula
\( u_8 = 2 \times 3^{8-1} \)
\( u_8 = 2 \times 3^7 \)
\( u_8 = 2 \times 2187 \)
\( u_8 = 4374 \)
โ The 8th term is 4374
โ๏ธ Geometric Series
Definition
A geometric series is the sum of the terms in a geometric sequence.
๐ Sum of First n Terms (Finite Series)
โ ๏ธ Use when \( r \neq 1 \)
Formula (most common form):
\[ S_n = \frac{u_1(r^n - 1)}{r - 1} \quad \text{when } r > 1 \]
Alternative form:
\[ S_n = \frac{u_1(1 - r^n)}{1 - r} \quad \text{when } r < 1 \]
๐ก Both formulas are equivalent! Choose whichever is easier for your calculation.
โพ๏ธ Sum to Infinity (Infinite Series)
โ ๏ธ Only converges when \( |r| < 1 \) (i.e., -1 < r < 1)
\[ S_\infty = \frac{u_1}{1 - r} \]
Convergence Rules:
- If \( |r| < 1 \): Series converges (has a finite sum)
- If \( |r| \geq 1 \): Series diverges (sum approaches infinity)
๐ Worked Example: Geometric Series
Find the sum of the first 6 terms: 3 + 6 + 12 + 24 + ...
Step 1: Identify the given values
\( u_1 = 3 \), \( r = \frac{6}{3} = 2 \), \( n = 6 \)
Step 2: Apply the formula (r > 1)
\( S_6 = \frac{3(2^6 - 1)}{2 - 1} \)
\( S_6 = \frac{3(64 - 1)}{1} \)
\( S_6 = 3 \times 63 = 189 \)
โ The sum is 189
ฮฃ Sigma Notation
What is Sigma Notation?
Sigma notation (ฮฃ) is a concise way to represent the sum of a sequence of terms. The Greek letter ฮฃ (capital sigma) means "sum".
๐ General Form
\[ \sum_{r=a}^{b} f(r) \]
Where:
- โข ฮฃ = sum symbol
- โข r = index of summation (can be any variable)
- โข a = lower limit (starting value)
- โข b = upper limit (ending value)
- โข f(r) = expression to be summed
๐ Worked Examples
Example 1: Evaluate \( \displaystyle\sum_{r=1}^{5} (2r + 3) \)
This means: Sum the expression (2r + 3) for r = 1, 2, 3, 4, 5
When r = 1: 2(1) + 3 = 5
When r = 2: 2(2) + 3 = 7
When r = 3: 2(3) + 3 = 9
When r = 4: 2(4) + 3 = 11
When r = 5: 2(5) + 3 = 13
Sum = 5 + 7 + 9 + 11 + 13 = 45
Example 2: Evaluate \( \displaystyle\sum_{k=3}^{6} k^2 \)
โ ๏ธ Note: Lower limit starts at 3, not 1!
When k = 3: \( 3^2 = 9 \)
When k = 4: \( 4^2 = 16 \)
When k = 5: \( 5^2 = 25 \)
When k = 6: \( 6^2 = 36 \)
Sum = 9 + 16 + 25 + 36 = 86
๐ Key Properties of Sigma Notation
1. Constant Multiple:
\[ \sum_{r=a}^{b} c \cdot f(r) = c \sum_{r=a}^{b} f(r) \]
2. Sum/Difference:
\[ \sum_{r=a}^{b} [f(r) \pm g(r)] = \sum_{r=a}^{b} f(r) \pm \sum_{r=a}^{b} g(r) \]
3. Sum of a Constant:
\[ \sum_{r=1}^{n} c = n \times c \]
๐ Quick Reference Formula Sheet
ARITHMETIC
nth Term:
\( u_n = u_1 + (n-1)d \)
Common Difference:
\( d = u_{n+1} - u_n \)
Sum (Formula 1):
\( S_n = \frac{n}{2}(u_1 + u_n) \)
Sum (Formula 2):
\( S_n = \frac{n}{2}[2u_1 + (n-1)d] \)
GEOMETRIC
nth Term:
\( u_n = u_1 \cdot r^{n-1} \)
Common Ratio:
\( r = \frac{u_{n+1}}{u_n} \)
Finite Sum:
\( S_n = \frac{u_1(r^n - 1)}{r - 1} \)
Infinite Sum (|r| < 1):
\( S_\infty = \frac{u_1}{1 - r} \)
๐ฏ IB Exam Tips & Strategies
๐ก Tip 1: Use Your GDC (Calculator) Wisely
Your calculator can evaluate sigma notation and check sums! Use it to verify answers, but always show your working for full marks.
Calculator functions: Look for "sum(" or "ฮฃ" in your GDC menu.
๐ก Tip 2: Know Which Formula to Use
Arithmetic sum: Use Formula 1 if you know first and last terms; use Formula 2 if you know common difference.
Geometric sum: Check if you need finite or infinite sum formula.
๐ก Tip 3: Identify the Sequence Type First
Check consecutive terms: If you add/subtract the same value โ Arithmetic. If you multiply/divide by the same value โ Geometric.
๐ก Tip 4: Watch for Simultaneous Equations
IB often gives you two pieces of information (e.g., "3rd term is 10 and 7th term is 22"). Set up two equations with \( u_1 \) and \( d \) (or \( r \)), then solve simultaneously.
๐ก Tip 5: Check Convergence for Infinite Series
Before using \( S_\infty = \frac{u_1}{1-r} \), always verify that \( |r| < 1 \). If \( |r| \geq 1 \), the series diverges and has no finite sum.
๐ก Tip 6: Be Careful with Sigma Notation Limits
Not all sigma notation starts at r = 1! Always check the lower limit. If it starts at r = 3, begin your sum from there, not from 1.
๐ก Tip 7: Application Problems
Finance: Compound interest uses geometric sequences.
Linear patterns: Saving the same amount weekly uses arithmetic sequences.
Population growth: Often modeled with geometric sequences.
โ Common Mistakes to Avoid
Mistake #1: Confusing n with \( u_n \)
n is the position of the term (1st, 2nd, 3rd, etc.)
\( u_n \) is the value of the nth term
โ Wrong: "Find the 5th term" โ Answer: 5
โ Correct: "Find the 5th term" โ Answer: \( u_5 \) = (calculated value)
Mistake #2: Using Wrong Exponent in Geometric Formula
The exponent is (n - 1), not n!
โ Wrong: \( u_n = u_1 \cdot r^n \)
โ Correct: \( u_n = u_1 \cdot r^{n-1} \)
Mistake #3: Forgetting to Check Convergence
Always check if \( |r| < 1 \) before using the infinite sum formula!
If r = 2, the series diverges โ no finite sum exists!
Mistake #4: Misidentifying Sequence Type
Always test: Subtract consecutive terms (arithmetic?) OR divide consecutive terms (geometric?)
Sequence: 2, 4, 8, 16, ...
โ Arithmetic? 4 - 2 = 2, but 8 - 4 = 4 (not constant!)
โ Geometric! 4/2 = 2, 8/4 = 2, 16/8 = 2 (constant ratio!)
โ๏ธ Practice Problems
Try these IB-style problems, then click to reveal solutions!
Problem 1: Arithmetic Sequence
The 4th term of an arithmetic sequence is 17 and the 9th term is 37. Find the first term and common difference.
Solution:
Using \( u_n = u_1 + (n-1)d \):
\( u_4 = u_1 + 3d = 17 \) ... (1)
\( u_9 = u_1 + 8d = 37 \) ... (2)
Subtract equation (1) from (2):
\( 5d = 20 \) โ \( d = 4 \)
Substitute back into (1):
\( u_1 + 3(4) = 17 \) โ \( u_1 = 5 \)
Answer: \( u_1 = 5 \), \( d = 4 \)
Click to reveal solution โผ
Problem 2: Geometric Sequence
A geometric sequence has first term 6 and common ratio 0.5. Find the sum to infinity.
Solution:
Check convergence: \( |r| = |0.5| = 0.5 < 1 \) โ Series converges
Use formula: \( S_\infty = \frac{u_1}{1-r} \)
\( S_\infty = \frac{6}{1-0.5} = \frac{6}{0.5} = 12 \)
Answer: \( S_\infty = 12 \)
Click to reveal solution โผ
Problem 3: Sigma Notation
Evaluate \( \displaystyle\sum_{r=2}^{6} (3r - 1) \)
Solution:
โ ๏ธ Note: Starts at r = 2
When r = 2: 3(2) - 1 = 5
When r = 3: 3(3) - 1 = 8
When r = 4: 3(4) - 1 = 11
When r = 5: 3(5) - 1 = 14
When r = 6: 3(6) - 1 = 17
Sum = 5 + 8 + 11 + 14 + 17 = 55
Answer: 55
Click to reveal solution โผ
Problem 4: Arithmetic Series Application
Arturo swims 200m in week 1. Each week he swims 30m more than the previous week. How far does he swim altogether in 52 weeks?
Solution:
This is an arithmetic series with:
\( u_1 = 200 \), \( d = 30 \), \( n = 52 \)
Use: \( S_n = \frac{n}{2}[2u_1 + (n-1)d] \)
\( S_{52} = \frac{52}{2}[2(200) + (52-1)(30)] \)
\( S_{52} = 26[400 + 51 \times 30] \)
\( S_{52} = 26[400 + 1530] \)
\( S_{52} = 26 \times 1930 = 50,180 \)
Answer: 50,180 metres
Click to reveal solution โผ
Problem 5 (Challenge): Mixed Sequences
A sequence is defined by \( u_1 = 3 \), \( u_2 = 12 \), \( u_3 = 48 \). Find \( u_6 \).
Solution:
Check if arithmetic: 12 - 3 = 9, but 48 - 12 = 36 (not constant) โ
Check if geometric: \( \frac{12}{3} = 4 \), \( \frac{48}{12} = 4 \) (constant!) โ
This is geometric with \( u_1 = 3 \), \( r = 4 \)
\( u_6 = 3 \times 4^{6-1} = 3 \times 4^5 \)
\( u_6 = 3 \times 1024 = 3072 \)
Answer: \( u_6 = 3072 \)
Click to reveal solution โผ
๐ Key Takeaways
โ Arithmetic: Constant difference between terms (addition/subtraction)
โ Geometric: Constant ratio between terms (multiplication/division)
โ Sigma notation: Compact way to write sums
โ Convergence: Geometric series with |r| < 1 have finite infinite sums
โ IB Formula Booklet: All main formulas are provided โ know when to use each!
Master these concepts and you'll excel in IB Math AA SL sequences and series questions! ๐