Unit 1.5 – Determining Limits Using Algebraic Properties of Limits
AP® Calculus AB & BC | Formula Reference Sheet
Core Concept: The algebraic properties of limits (also called limit laws or limit theorems) allow us to break down complex limit problems into simpler pieces. These properties are the foundation for evaluating limits without graphing or tables—just using algebra!
🎯 The Direct Substitution Principle
If \(f(x)\) is continuous at \(x = a\), then:
Meaning: For continuous functions (polynomials, most trig functions, exponentials, etc.), you can find the limit by direct substitution—just plug in the value!
📝 Key Point: Direct substitution works for:
- Polynomials: \(\lim_{x \to a} p(x) = p(a)\)
- Rational functions: \(\lim_{x \to a} \frac{p(x)}{q(x)} = \frac{p(a)}{q(a)}\) (if \(q(a) \neq 0\))
- Radicals: \(\lim_{x \to a} \sqrt[n]{f(x)} = \sqrt[n]{f(a)}\) (when defined)
- Trig functions: \(\lim_{x \to a} \sin(x) = \sin(a)\), etc. (at valid points)
📚 The Complete Limit Laws
Given: \(\lim_{x \to a} f(x) = L\) and \(\lim_{x \to a} g(x) = M\) (both exist and are finite)
Then the following properties hold:
1. Constant Law
Rule: The limit of a constant is just the constant itself.
Example: \(\lim_{x \to 5} 7 = 7\)
2. Identity Law
Rule: As \(x\) approaches \(a\), the limit of \(x\) is \(a\).
Example: \(\lim_{x \to 3} x = 3\)
3. Sum Law
Rule: The limit of a sum is the sum of the limits.
Example: \(\lim_{x \to 2} (x^2 + 3x) = \lim_{x \to 2} x^2 + \lim_{x \to 2} 3x = 4 + 6 = 10\)
4. Difference Law
Rule: The limit of a difference is the difference of the limits.
Example: \(\lim_{x \to 3} (x^2 - 2x) = 9 - 6 = 3\)
5. Constant Multiple Law
Rule: The limit of a constant times a function is the constant times the limit of the function.
Example: \(\lim_{x \to 4} 5x^2 = 5 \cdot \lim_{x \to 4} x^2 = 5 \cdot 16 = 80\)
6. Product Law
Rule: The limit of a product is the product of the limits.
Example: \(\lim_{x \to 2} (x \cdot x^2) = 2 \cdot 4 = 8\)
7. Quotient Law
Rule: The limit of a quotient is the quotient of the limits, as long as the denominator's limit is not zero.
Example: \(\lim_{x \to 3} \frac{x^2 + 1}{2x} = \frac{10}{6} = \frac{5}{3}\)
⚠️ Critical Condition: The quotient law only works when \(M \neq 0\). If the denominator's limit is zero, you cannot use this property directly—you need algebraic manipulation (see Unit 1.6).
8. Power Law
Rule: The limit of a function to a power \(n\) is the limit raised to that power.
Example: \(\lim_{x \to 2} (x + 1)^3 = 3^3 = 27\)
9. Root Law
Conditions:
- If \(n\) is odd: Works for all \(L\)
- If \(n\) is even: \(L \geq 0\) required
Example: \(\lim_{x \to 4} \sqrt{2x + 1} = \sqrt{9} = 3\)
📋 Quick Reference: All Limit Laws
| Property | Formula | Condition |
|---|---|---|
| Constant | \(\lim_{x \to a} c = c\) | Always |
| Identity | \(\lim_{x \to a} x = a\) | Always |
| Sum | \(\lim [f + g] = L + M\) | Both limits exist |
| Difference | \(\lim [f - g] = L - M\) | Both limits exist |
| Constant Multiple | \(\lim [c \cdot f] = c \cdot L\) | Limit exists |
| Product | \(\lim [f \cdot g] = L \cdot M\) | Both limits exist |
| Quotient | \(\lim \frac{f}{g} = \frac{L}{M}\) | Both exist, \(M \neq 0\) |
| Power | \(\lim [f]^n = L^n\) | Limit exists |
| Root | \(\lim \sqrt[n]{f} = \sqrt[n]{L}\) | \(L \geq 0\) for even \(n\) |
🔗 Limits of Composite Functions
If \(\lim_{x \to a} g(x) = L\) and \(f\) is continuous at \(L\), then:
In words: For continuous outer functions, you can "pull the limit inside."
Example: \(\lim_{x \to 2} \sin(x^2)\)
- Inner limit: \(\lim_{x \to 2} x^2 = 4\)
- Outer function: \(\sin(x)\) is continuous at \(x = 4\)
- Apply composition law: \(\lim_{x \to 2} \sin(x^2) = \sin(4)\)
🎯 How to Apply the Limit Laws
General Strategy:
- Try direct substitution first: If the function is continuous, just plug in the value
- Break into pieces: Use sum, difference, product, quotient laws to separate complex expressions
- Evaluate each piece: Find the limit of each component separately
- Combine results: Put the pieces back together using the appropriate law
- Check conditions: Make sure denominators aren't zero, roots are defined, etc.
📚 Worked Examples
Example 1: Polynomial Limit
Find: \(\lim_{x \to 3} (2x^2 + 5x - 1)\)
Solution: Polynomials are continuous everywhere, so use direct substitution:
Example 2: Rational Function (Valid Denominator)
Find: \(\lim_{x \to 2} \frac{x^3 - 4x}{x + 3}\)
Solution:
- Check denominator: \(\lim_{x \to 2} (x + 3) = 5 \neq 0\) ✓
- Apply quotient law:
Example 3: Using Multiple Laws
Find: \(\lim_{x \to 1} 3(x^2 + 2)^4\)
Solution:
- Constant multiple law: \(\lim 3(x^2 + 2)^4 = 3 \cdot \lim (x^2 + 2)^4\)
- Power law: \(3 \cdot [\lim (x^2 + 2)]^4\)
- Sum law & direct substitution: \(3 \cdot [(1 + 2)]^4 = 3 \cdot 3^4 = 3 \cdot 81 = 243\)
Example 4: Square Root
Find: \(\lim_{x \to 5} \sqrt{3x + 1}\)
Solution:
- Root law: \(\lim \sqrt{3x + 1} = \sqrt{\lim (3x + 1)}\)
- Direct substitution: \(\sqrt{3(5) + 1} = \sqrt{16} = 4\)
⚠️ Special Cases & When Laws Don't Apply
Limit laws FAIL when:
- Denominator → 0: Quotient law doesn't apply if \(\lim g(x) = 0\)
- Indeterminate forms: Getting \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), \(0 \cdot \infty\), etc.
- One or both limits DNE: Can't use laws if individual limits don't exist
- Even root of negative: \(\sqrt{-4}\) is undefined in real numbers
What to Do When Direct Substitution Fails
If direct substitution gives you 0/0 or another indeterminate form, you need algebraic manipulation:
- Factor and cancel (Unit 1.6)
- Rationalize (multiply by conjugate)
- Combine fractions
- Use special limit theorems
- L'Hôpital's Rule (later in calculus)
💡 Tips, Tricks & Mnemonics
✅ Essential Tips
- ALWAYS try direct substitution first: It's the fastest method when it works
- Check the denominator: Before using quotient law, verify it's not approaching zero
- Work inside-out: For nested functions, evaluate innermost limits first
- Factor when possible: If direct substitution fails, try factoring
- Know your continuous functions: Polynomials, sin, cos, e^x, ln(x) are continuous on their domains
🎯 Mnemonic for Limit Laws
Memory Aid: "S-D-C-P-Q-P-R-C"
- Sum
- Difference
- Constant Multiple
- Product
- Quotient
- Power
- Root
- Composition
Or use: "Smart Cats Play Quietly, Producing Peaceful Relaxing Compositions"
🔍 Quick Diagnostic Flowchart
Finding a Limit? Follow This:
- Is it continuous at that point? → YES: Use direct substitution (done!)
- NO: Does direct substitution give 0/0?
- YES: Use algebraic manipulation (factor, rationalize)
- NO: Check if it gives ∞ or DNE → analyze further
- Can you break it into pieces? → Use sum, difference, product, quotient laws
- Is it a composition? → Check if outer function is continuous at inner limit
❌ Common Mistakes to Avoid
- Mistake 1: Using quotient law when denominator → 0 (must factor first!)
- Mistake 2: Forgetting to check continuity for composition law
- Mistake 3: Canceling before verifying the factor doesn't make x = a undefined
- Mistake 4: Applying laws when one or both individual limits don't exist
- Mistake 5: Taking square root of a negative limit (undefined in reals)
- Mistake 6: Not recognizing when direct substitution works—always try it first!
📝 How to Master These Properties
Effective Practice Strategy:
- Memorize the laws: Use flashcards or the mnemonic
- Start simple: Practice with polynomials first (always works)
- Identify which laws apply: Before solving, name the properties you'll use
- Work both directions: Given a limit, evaluate it; given a value, construct a matching limit
- Check conditions: Always verify denominators aren't zero, roots are valid, etc.
- Recognize when they don't apply: Practice identifying indeterminate forms
- Time yourself: AP® exam limits should be quick with these laws
🌟 Special Limits to Know
These will be covered more in later units, but are worth noting:
✏️ AP® Exam Tips
What the AP® Exam Expects:
- Know which law to use: On FRQs, you may need to justify which property applies
- Show your work: Write out the steps—don't just give the final answer
- Check conditions: Explicitly verify denominators aren't zero
- Use proper notation: Write \(\lim_{x \to a}\) clearly, not just "lim"
- Direct substitution is your friend: Use it whenever possible—it's fastest
- Multiple choice strategy: Eliminate answers that violate limit laws
- Watch for traps: Problems that look simple but have hidden discontinuities
🔢 Special Case: Polynomials & Rational Functions
For any polynomial \(p(x)\):
Polynomials are continuous everywhere, so direct substitution always works!
For rational function \(r(x) = \frac{p(x)}{q(x)}\):
If \(q(a) = 0\), you cannot use direct substitution—need algebraic manipulation!
⚡ Quick Reference Card
| If You See... | Use This Law | Formula |
|---|---|---|
| \(f(x) + g(x)\) | Sum Law | \(\lim [f + g] = L + M\) |
| \(f(x) - g(x)\) | Difference Law | \(\lim [f - g] = L - M\) |
| \(c \cdot f(x)\) | Constant Multiple | \(\lim [c \cdot f] = c \cdot L\) |
| \(f(x) \cdot g(x)\) | Product Law | \(\lim [f \cdot g] = L \cdot M\) |
| \(\frac{f(x)}{g(x)}\) | Quotient Law | \(\lim \frac{f}{g} = \frac{L}{M}\) (\(M \neq 0\)) |
| \([f(x)]^n\) | Power Law | \(\lim [f]^n = L^n\) |
| \(\sqrt[n]{f(x)}\) | Root Law | \(\lim \sqrt[n]{f} = \sqrt[n]{L}\) |
| \(f(g(x))\) | Composition | \(\lim f(g(x)) = f(L)\) (\(f\) continuous) |
🔗 Connection to Other Topics
Unit 1.5 is foundational for:
- Unit 1.6: Algebraic manipulation (when these properties aren't enough)
- Unit 1.7-1.9: Continuity (uses limit properties to define continuous functions)
- Unit 2: Derivatives (limit definition uses these properties)
- Unit 3: Derivative rules (mirror these limit laws)
- Unit 6: Integration properties (similar sum, difference, constant multiple rules)
- All of calculus: These are the building blocks for everything!
Remember: The algebraic properties of limits are power tools that let you evaluate complex limits by breaking them into simple pieces. Master these nine laws (plus the composition rule), and you'll be able to tackle most limit problems with confidence. When direct substitution works, use it—it's fast! When it doesn't, Unit 1.6 has your back with algebraic manipulation techniques. 🎯✨